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A mathematical conjecture


Haile
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DISCLAIMER: THIS IS ALL PROBABLY JUST A COINCIDENCE

I've always been a bit of a numberphile.  The other day, when I went to figure out just how worth it paying an upgrade was for a girl versus the fighting the upper limit of Fredy, I discovered something interesting (spoilers: if she's under five stars fight, otherwise save Kobans).  Shaving off the thousands, I found that one Koban is worth about 2,731.4814...k each relative to Fredy's upper limit, or in other words, 590/216.  That number looked oddly familiar to me, so I tried adding one to the denominator.  There, I got about 2.7188940092165898617511520737327.  That was looking VERY familiar to me, since e -a very important number in math- is about 2.7182818284590452353602874713527- less than 0.0225% of a difference.  Hence, I propose that with some simple rounding errors added into the mix, the internal equation for Koband to in-money conversion is y = 1000e(x+1), wherein y is money and x is Kobans at the optimal rate of mob fighting, while x is not equal to zero.

Edited by Haile
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i think "numberphile" is an understatement. 🤣

anyways i think your conclusive formula has an error. as you can buy refills down to a single minute it would result in 1000e * (0.36 + 1) = 3,696.86328670. scaling that up to 30 minutes (which corresponds 1 bp) would mean roko must drop 110,905.898601 cash.

also if you go back in time to where finalmecia was the highest money awarding troll the relation would be 530k/216 = 2.45370370370k (or 530k/217 = 2.44239631336k). i doubt those numbers correspond to a natural constant.

Edited by Habi
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I doubt it too, just found it interesting.  I did look into buying refills by the minute.  Because the cost in Kobans is rounded to whole numbers, I couldn't make a more straightforward equation, so I went with the refill cost the second after the combativity hits 0 with 30 minutes remaining.

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